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CLASS 12 PHYSICAL EDUCATION SYLLABUS 2024-25

CLASS 12 PHYSICAL EDUCATION SYLLABUS 2024-25

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1 .A student received grades of 85, 76, 93, 82, and 96 in five subjects. Determine the arithmetic mean of the grades.

To determine the arithmetic mean (average) of the grades, you add up all the grades and then divide by the number of grades.

Arithmetic Mean =Sum of Grades / Number of Grades

​For the grades of 85, 76, 93, 82, and 96, the sum is:

85+76+93+82+96= 432

There are 5 grades in total. So, the arithmetic mean is:

Arithmetic Mean =432/5

= 86.4


2.The reaction times of an individual to certain stimuli were measured by a psychologist to be 0.53, 0.46, 0.50, 0.49, 0.52, 0.53, 0.44, and 0.55 seconds respectively. Determine the mean reaction time of the individual to the stimuli


To find the mean reaction time of the individual, you need to add up all the measured reaction times and then divide by the number of measurements.

Let's add up the given reaction times:

0.53+0.46+0.50+0.49+0.52+0.53+0.44+0.55=4.920.53+0.46+0.50+0.49+0.52+0.53+0.44+0.55=4.92

Now, there are 8 measurements in total. So, to find the mean reaction time, divide the sum by 8:

Mean Reaction Time=4.928≈0.615Mean Reaction Time=84.92​≈0.615

Therefore, the mean reaction time of the individual to the stimuli is approximately 0.615 seconds.


3. A set of numbers consists of six 6’s, seven 7’s, eight 8’s, nine 9’s and ten 10’s. What is the arithmetic mean of the numbers?

To find the arithmetic mean of a set of numbers, you add up all the numbers and then divide by the total count of numbers.

In this case, you have:


· Six 6's

· Seven 7's

· Eight 8's

· Nine 9's

· Ten 10's


Let's calculate the sum of all these numbers:

(6×6)+(7×7)+(8×8)+(9×9)+(10×10)(6×6)+(7×7)+(8×8)+(9×9)+(10×10) =(36)+(49)+(64)+(81)+(100)=(36)+(49)+(64)+(81)+(100) =330=330

Now, you add up the counts of each number:

6+7+8+9+10=406+7+8+9+10=40

Finally, you divide the sum of all the numbers by the total count of numbers:

Arithmetic Mean=33040=8.25Arithmetic Mean=40330​=8.25

So, the arithmetic mean of the numbers is 8.25.


4. A student’s grades in the laboratory, lecture, and recitation parts of a physics course were 71, 78, and 89, respectively.

(a) If the weights accorded these grades are 2, 4, and 5, respectively, what is an appropriate average grade?

(b) What is the average grade if equal weights are used?

To find the average grade, we will first calculate the weighted average using the given weights, and then we will calculate the average grade with equal weights.

(a) Weighted Average Grade: Given weights for laboratory, lecture, and recitation are 2, 4, and 5 respectively, and the corresponding grades are 71, 78, and 89.

Weighted Average = (Weight for lab * Lab Grade + Weight for lecture * Lecture Grade + Weight for recitation * Recitation Grade) / Total Weight

Weighted Average = (2 * 71 + 4 * 78 + 5 * 89) / (2 + 4 + 5) Weighted Average = (142 + 312 + 445) / 11 Weighted Average = 899 / 11 Weighted Average ≈ 81.73

So, the weighted average grade is approximately 81.73.

(b) Average Grade with Equal Weights: If we use equal weights for all parts (lab, lecture, and recitation), each part will contribute equally to the average.

Average Grade = (Lab Grade + Lecture Grade + Recitation Grade) / 3 Average Grade = (71 + 78 + 89) / 3 Average Grade = 238 / 3 Average Grade ≈ 79.33

So, the average grade with equal weights is approximately 79.33.


5. Three teachers of economics reported mean examination grades of 79, 74, and 82 in their classes, which consisted of 32, 25, and 17 students, respectively. Determine the mean grade for all the classes.

To determine the mean grade for all the classes, we'll first calculate the weighted average of the mean examination grades based on the number of students in each class.

Weighted Average Grade = (Mean Grade for Class 1 * Number of Students in Class 1 + Mean Grade for Class 2 * Number of Students in Class 2 + Mean Grade for Class 3 * Number of Students in Class 3) / Total Number of Students

Given: Mean grade for Class 1 = 79, Number of students in Class 1 = 32 Mean grade for Class 2 = 74, Number of students in Class 2 = 25 Mean grade for Class 3 = 82, Number of students in Class 3 = 17

Weighted Average Grade = (79 * 32 + 74 * 25 + 82 * 17) / (32 + 25 + 17) Weighted Average Grade = (2528 + 1850 + 1394) / 74 Weighted Average Grade = 5772 / 74 Weighted Average Grade ≈ 78.00

So, the mean grade for all the classes is approximately 78.00.


6. Find the mean and median of these sets of numbers:

(a) 5, 4, 8, 3, 7, 2, 9

(b) 18.3, 20.6, 19.3, 22.4, 20.2, 18.8, 19.7, 20.0

Let's find the mean and median for each set of numbers:

(a) Set of numbers: 5, 4, 8, 3, 7, 2, 9

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (5 + 4 + 8 + 3 + 7 + 2 + 9) / 7 Mean = 38 / 7 Mean ≈ 5.43

To find the median: First, arrange the numbers in ascending order: 2, 3, 4, 5, 7, 8, 9 Since there are 7 numbers, the median will be the middle number, which is 5.

So, for set (a), the mean is approximately 5.43 and the median is 5.

(b) Set of numbers: 18.3, 20.6, 19.3, 22.4, 20.2, 18.8, 19.7, 20.0

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (18.3 + 20.6 + 19.3 + 22.4 + 20.2 + 18.8 + 19.7 + 20.0) / 8 Mean = 159.3 / 8 Mean = 19.91

To find the median: First, arrange the numbers in ascending order: 18.3, 18.8, 19.3, 19.7, 20.0, 20.2, 20.6, 22.4 Since there are 8 numbers, the median will be the average of the middle two numbers, which are 19.7 and 20.0. Median = (19.7 + 20.0) / 2 Median = 39.7 / 2 Median = 19.85

So, for set (b), the mean is 19.91 and the median is 19.85.


7. Find the mean, median, and mode for each set of numbers:

(a) 7, 4, 10, 9, 15, 12, 7, 9, 7

(b) 8, 11, 4, 3, 2, 5, 10, 6, 4, 1, 10, 8, 12, 6, 5, 7

1. t's find the mean, median, and mode for each set of numbers:

(a) Set of numbers: 7, 4, 10, 9, 15, 12, 7, 9, 7

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (7 + 4 + 10 + 9 + 15 + 12 + 7 + 9 + 7) / 9 Mean = 80 / 9 Mean ≈ 8.89

To find the median: First, arrange the numbers in ascending order: 4, 7, 7, 7, 9, 9, 10, 12, 15 Since there are 9 numbers, the median will be the middle number, which is 9.

To find the mode: The mode is the number that appears most frequently in the set. In this case, 7 appears three times, making it the mode.

So, for set (a), the mean is approximately 8.89, the median is 9, and the mode is 7.

(b) Set of numbers: 8, 11, 4, 3, 2, 5, 10, 6, 4, 1, 10, 8, 12, 6, 5, 7

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (8 + 11 + 4 + 3 + 2 + 5 + 10 + 6 + 4 + 1 + 10 + 8 + 12 + 6 + 5 + 7) / 16 Mean = 102 / 16 Mean = 6.375

To find the median: First, arrange the numbers in ascending order: 1, 2, 3, 4, 4, 5, 5, 6, 6, 7, 8, 8, 10, 10, 11, 12 Since there are 16 numbers, the median will be the average of the middle two numbers, which are 6 and 6. Median = (6 + 6) / 2 Median = 12 / 2 Median = 6

To find the mode: The mode is the number that appears most frequently in the set. In this case, both 4 and 10 appear twice, making them the modes.

So, for set (b), the mean is 6.375, the median is 6, and the modes are 4 and 10.

8.Find the geometric mean of the numbers a) 4.2 and 16.8

To find the geometric mean of two numbers, you multiply them together and then take the square root of the product. The formula for the geometric mean of two numbers �a and �b is:

Geometric Mean=�×�Geometric Mean=a×b​

For the numbers 4.2 and 16.8, we can plug them into the formula:

Geometric Mean=4.2×16.8Geometric Mean=4.2×16.8​

Geometric Mean=70.56Geometric Mean=70.56​

Geometric Mean≈8.4Geometric Mean≈8.4

So, the geometric mean of 4.2 and 16.8 is approximately 8.4.a

Find the range of the sets (a) 5, 3, 8, 4, 7, 6, 12, 4, 3 and (b) 8.772, 6.453, 10.624, 8.628, 9.434, 6.351

To find the range of a set of numbers, you need to subtract the smallest number from the largest number in the set. Let's calculate the range for each set:

(a) Set: 5, 3, 8, 4, 7, 6, 12, 4, 3 The smallest number in the set is 3, and the largest number is 12. Range = Largest number - Smallest number Range = 12 - 3 = 9 So, the range of set (a) is 9.

(b) Set: 8.772, 6.453, 10.624, 8.628, 9.434, 6.351 The smallest number in the set is 6.351, and the largest number is 10.624. Range = Largest number - Smallest number Range = 10.624 - 6.351 ≈ 4.273 (rounded to three decimal places) So, the range of set (b) is approximately 4.273.

Find the mean deviation of the set (a)3,7,9,5and(b) 2.4, 1.6, 3.8, 4.1, 3.4

To find the mean deviation of a set of numbers, follow these steps:Calculate the mean (average) of the set.
Find the absolute difference between each number in the set and the mean.
Calculate the mean of these absolute differences.

Let's start with set (a):

a) Set: 3, 7, 9, 5Mean (average) = (3 + 7 + 9 + 5) / 4 = 24 / 4 = 6

Now, find the absolute differences between each number and the mean:

|3 - 6| = 3 |7 - 6| = 1 |9 - 6| = 3 |5 - 6| = 1Calculate the mean of these absolute differences:

Mean deviation = (3 + 1 + 3 + 1) / 4 = 8 / 4 = 2

So, the mean deviation of set (a) is 2.

Now, let's move on to set (b):

b) Set: 2.4, 1.6, 3.8, 4.1, 3.4Mean (average) = (2.4 + 1.6 + 3.8 + 4.1 + 3.4) / 5 = 15.3 / 5 = 3.06

Now, find the absolute differences between each number and the mean:

|2.4 - 3.06| = 0.66 |1.6 - 3.06| = 1.46 |3.8 - 3.06| = 0.74 |4.1 - 3.06| = 1.04 |3.4 - 3.06| = 0.34Calculate the mean of these absolute differences:

Mean deviation = (0.66 + 1.46 + 0.74 + 1.04 + 0.34) / 5 ≈ 0.864

So, the mean deviation of set (b) is approximately 0.864.

Basic syntax

Basic syntax refers to the fundamental rules and structure that govern how programming languages are written. Each programming language has its own syntax, which includes rules for writing code, organizing statements, defining variables, and specifying actions or functions. Here are some key components of basic syntax:

Statements: A statement is a single line of code that performs a specific task. Statements can include variable declarations, function calls, conditional expressions, loops, and more.


Variables: Variables are used to store data values that can be manipulated and accessed throughout the program. They are typically declared with a specific data type (e.g., integer, string, boolean) and a name that uniquely identifies them within the program.


Data Types: Programming languages support various data types, such as integers, floating-point numbers, strings, characters, booleans, arrays, and objects. Each data type has specific rules for how data is stored and manipulated.


Operators: Operators are symbols or keywords that perform operations on one or more operands. Examples of operators include arithmetic operators (+, -, *, /), comparison operators (==, !=, <, >), logical operators (&&, ||, !), and assignment operators (=, +=, -=).


Control Structures: Control structures are used to control the flow of execution in a program. Common control structures include conditional statements (if-else, switch), loops (for, while, do-while), and branching statements (break, continue, return).

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