Friday 19 July 2024

CLASS 7 BALBHARTI SOLUTIONS

CLASS 7 BALBHARTI SOLUTIONS 


CLICK SOLUTION LINKS BELOW

1. CLASS 7 ENGLISH SOLUTIONS CLICK HERE 👈👈👈

2. CLASS 7 HINDI SOLUTIONS CLICK HERE 👈👈👈

3. CLASS 7 MATHS SOLUTIONS CLICK HERE 👈👈👈

4. CLASS 7 MARATHI SOLUTIONS CLICK HERE 👈👈👈

5. CLASS 7 HISTORY SOLUTIONS CLICK HERE 👈👈👈

6. CLASS 7 GEOGRAPHY SOLUTIONS CLICK HERE 👈👈👈

7. CLASS 7 SCIENCE SOLUTIONS CLICK HERE 👈👈👈

8. CLASS 7 CIVICS SOLUTIONS CLICK HERE 👈👈👈


Wednesday 3 July 2024

CLASS 5 BALBHARTI SOLUTIONS

CLASS 5 BALBHARTI SOLUTIONS 



CLICK SOLUTIONS LINKS BELOW 

1. CLASS 5 ENGLISH SOLUTIONS CLICK HERE 👈👈👈

2. CLASS 5 HINDI SOLUTIONS CLICK HERE 👈👈👈

3. CLASS 5 MATHS SOLUTIONS CLICK HERE 👈👈👈

4. CLASS 5 MARATHI SOLUTIONS CLICK HERE 👈👈👈

5. CLASS 5 EVS SOLUTIONS CLICK HERE 👈👈👈

Monday 24 June 2024

Html code for online photoediting tool

HTML Code for online photo editing tool

Copy paste the below code in notepad

<!DOCTYPE html>

<html lang="en">

<head>

<meta charset="UTF-8">

<meta name="viewport" content="width=device-width, initial-scale=1.0">

<title>Online Photo Editor</title>

<style>

    body {

        font-family: Arial, sans-serif;

        text-align: center;

    }

    #canvas {

        border: 1px solid #ccc;

        margin-top: 20px;

    }

    button {

        margin: 10px;

        padding: 8px 16px;

        font-size: 16px;

        cursor: pointer;

    }

</style>

</head>

<body>

    <h1>Online Photo Editor</h1>

    <input type="file" id="fileInput">

    <br>

    <button onclick="resizeImage()">Resize</button>

    <button onclick="grayscale()">Grayscale</button>

    <button onclick="adjustBrightness()">Brightness</button>

    <button onclick="adjustContrast()">Contrast</button>

    <button onclick="downloadImage()">Download</button>

    <br>

    <canvas id="canvas" width="600" height="400"></canvas>


    <script>

        const canvas = document.getElementById('canvas');

        const ctx = canvas.getContext('2d');

        let img = new Image();


        function loadImage(event) {

            img.onload = function() {

                ctx.clearRect(0, 0, canvas.width, canvas.height);

                ctx.drawImage(img, 0, 0, canvas.width, canvas.height);

            };

            img.src = URL.createObjectURL(event.target.files[0]);

        }


        function resizeImage() {

            canvas.width = img.width / 2;

            canvas.height = img.height / 2;

            ctx.drawImage(img, 0, 0, canvas.width, canvas.height);

        }


        function grayscale() {

            let imageData = ctx.getImageData(0, 0, canvas.width, canvas.height);

            let data = imageData.data;

            for (let i = 0; i < data.length; i += 4) {

                let avg = (data[i] + data[i + 1] + data[i + 2]) / 3;

                data[i] = avg;

                data[i + 1] = avg;

                data[i + 2] = avg;

            }

            ctx.putImageData(imageData, 0, 0);

        }


        function adjustBrightness() {

            let imageData = ctx.getImageData(0, 0, canvas.width, canvas.height);

            let data = imageData.data;

            let adjustment = 20;

            for (let i = 0; i < data.length; i += 4) {

                data[i] += adjustment;

                data[i + 1] += adjustment;

                data[i + 2] += adjustment;

            }

            ctx.putImageData(imageData, 0, 0);

        }


        function adjustContrast() {

            let imageData = ctx.getImageData(0, 0, canvas.width, canvas.height);

            let data = imageData.data;

            let factor = (259 * (100 + 50)) / (255 * (259 - 50));

            for (let i = 0; i < data.length; i += 4) {

                data[i] = factor * (data[i] - 128) + 128;

                data[i + 1] = factor * (data[i + 1] - 128) + 128;

                data[i + 2] = factor * (data[i + 2] - 128) + 128;

            }

            ctx.putImageData(imageData, 0, 0);

        }


        function downloadImage() {

            let download = document.createElement('a');

            download.href = canvas.toDataURL();

            download.download = 'edited_image.png';

            download.click();

        }


        document.getElementById('fileInput').addEventListener('change', loadImage, false);

    </script>

</body>

</html>


Sunday 16 June 2024

Speed Checker Tool

 HTML CODE TO GENERATE A INTERNET SPEED CHECKER TOOL 

<!DOCTYPE html>

<html>

<head>

  <title>Fast.com Web View</title>

  <style>

    html, body {

      margin: 0;

      padding: 0;

      height: 100%;

    }

    #webview {

      width: 100%;

      height: 100%;

      border: none;

    }

  </style>

</head>

<body>

  <iframe id="webview"></iframe>


  <script>

    window.onload = function() {

      var webview = document.getElementById("webview");


      function resizeWebview() {

        webview.style.height = window.innerHeight + "px";

      }


      // Resize the web view when the window is resized

      window.addEventListener("resize", resizeWebview);


      // Load the Fast.com website into the web view

      webview.src = "https://fast.com";


      // Initially resize the web view

      resizeWebview();

    };

  </script>

</body>

</html>

Saturday 15 June 2024

Mumbai University BSC Syllabus



Click on links below to download pdf

BSC Data Science  đŸ‘ˆđŸ‘ˆ click here to download pdf 

BSC computer science  👈👈 click here to download pdf 

 BSC IT  đŸ‘ˆđŸ‘ˆ click here to download pdf 




Wednesday 29 May 2024

Free Computer Course

 Free Computer Course with certificate 👑

Click below 👇 👇 👇.


Sunday 26 May 2024

Square root

 Watch click below 👇.



Wednesday 22 May 2024

EVS Project Report on E-Waste Management

EVS Project Report on E-Waste Management


Introduction:

Electronic waste, commonly known as e-waste, is a growing concern globally due to the rapid advancement of technology and the short lifespan of electronic devices. E-waste comprises discarded electronic devices like mobile phones, computers, televisions, and household appliances, which contain hazardous materials such as lead, mercury, cadmium, and chromium. Improper disposal of e-waste poses significant environmental and health risks as these toxic substances can leach into soil and water, contaminating the environment and endangering human health.

Importance

Proper management of e-waste is crucial for several reasons:

1. Environmental Protection: E-waste contains hazardous materials that can pollute the air, soil, and water if not disposed of properly. Managing e-waste ensures these toxins are safely recycled or disposed of, minimizing environmental contamination.

2. Resource Conservation: Electronic devices contain valuable resources like gold, silver, and copper. Recycling e-waste allows for the recovery of these materials, reducing the need for mining and conserving natural resources.

3. Health and Safety: Improper handling of e-waste exposes individuals to harmful chemicals and pollutants, leading to various health problems. Effective e-waste management protects both human health and the environment.

4. Economic Benefits: Proper disposal and recycling of e-waste create opportunities for job creation and revenue generation through the recovery of valuable materials.



Objectives

The objectives of this project on e-waste management are as follows:

1. To raise awareness about the environmental and health hazards associated with improper e-waste disposal.

2. To promote responsible e-waste management practices among individuals, businesses, and governments.

3. To assess the current state of e-waste management in a specific region or community.

4. To propose sustainable solutions for the collection, recycling, and disposal of e-waste.

5. To evaluate the effectiveness of existing e-waste management policies and initiatives.



Methodology

1. Literature Review: Conduct research to understand the environmental impact of e-waste and existing management practices worldwide.

2. Surveys and Interviews: Gather data through surveys and interviews to assess public awareness and attitudes towards e-waste management.

3. Field Visits: Visit recycling facilities, landfills, and electronic waste collection centres to observe current practices and challenges first-hand.

4. Data Analysis: Analyse collected data to identify patterns, trends, and areas for improvement in e-waste management.

5. Stakeholder Engagement: Collaborate with government agencies, NGOs, businesses, and communities to develop sustainable e-waste management strategies.



Observations

During the course of the project, several key observations were made:

1. Limited Awareness: Many individuals are unaware of the environmental and health risks associated with improper e-waste disposal.

2. Informal Recycling Sector: In some areas, informal recyclers play a significant role in e-waste management, but they often lack proper training and equipment, leading to unsafe practices.

3. Inadequate Infrastructure: Many regions lack sufficient infrastructure for e-waste collection, recycling, and disposal, resulting in illegal dumping and environmental contamination.

4. Policy Gaps: Existing e-waste management policies may be insufficient or poorly enforced, hindering effective regulation and compliance.



Analysis

The analysis of data collected suggests that while progress has been made in e-waste management, significant challenges remain. Key findings include:

1. Low Recycling Rates: Despite increasing awareness, recycling rates for e-waste remain relatively low, indicating a need for improved collection and recycling infrastructure.

2. Health Impacts: Improper e-waste disposal continues to pose health risks to communities, particularly those living near landfills or informal recycling sites.

3. Economic Opportunities: Effective e-waste management presents opportunities for job creation, resource recovery, and economic development, but these benefits are often underutilized due to inadequate policies and infrastructure.



Results & Conclusion

The results of this project highlight the importance of addressing e-waste management as a critical environmental and public health issue. Sustainable solutions must involve collaboration between governments, businesses, civil society, and individuals to:

1. Increase awareness and education about the hazards of e-waste and the importance of responsible disposal.

2. Improve e-waste collection and recycling infrastructure to ensure safe and efficient handling of electronic waste.

3. Strengthen e-waste management policies and enforcement mechanisms to regulate the industry and promote compliance.

4. Support innovation and investment in e-waste recycling technologies to maximize resource recovery and minimize environmental impact.

In conclusion, effective e-waste management is essential for protecting the environment, conserving resources, and safeguarding human health. By taking proactive measures to address this growing challenge, we can create a more sustainable future for generations to come.

Sunday 19 May 2024

EVS Project on Solid Waste Management

EVS Project on Solid Waste Management

Introduction:

Solid waste management is a critical aspect of environmental sustainability and public health. With rapid urbanization and industrialization, the generation of solid waste has increased significantly, posing challenges in disposal and management. This project aims to delve into various aspects of solid waste management, including its importance, objectives, methodology, observations, analysis, and conclusions. Effective solid waste management is essential for maintaining a clean and healthy environment. Improper disposal of solid waste can lead to pollution of land, water, and air, causing harm to human health, wildlife, and ecosystems. By managing solid waste efficiently, we can mitigate environmental pollution, conserve resources, and promote sustainable development.

Importance:

Environmental Protection:

Proper solid waste management helps prevent pollution of land, water, and air, reducing the impact on ecosystems and wildlife.

Public Health:

Adequate waste management minimizes health risks associated with exposure to hazardous materials and disease vectors, such as mosquitoes and rodents, thus safeguarding public health.

Resource Conservation:

Recycling and waste minimization initiatives conserve natural resources by reducing the need for raw materials and energy-intensive production processes.

Prevention of Contamination:

Effective waste management prevents the contamination of soil and groundwater by toxic substances leaching from landfills, preserving water quality for drinking and agricultural purposes.

Aesthetic Improvement:

Proper waste disposal enhances the visual appeal of communities by reducing littering and the accumulation of waste in public spaces, promoting a cleaner and more attractive environment.

Climate Change Mitigation:

Managing organic waste through composting or anaerobic digestion reduces methane emissions, a potent greenhouse gas, thus contributing to climate change mitigation efforts.



Objectives:

1. To analyze the current status of solid waste generation in the study area.

2. To assess existing solid waste management practices and infrastructure.

3. To identify challenges and barriers in solid waste management.

4. To propose sustainable strategies for solid waste management.

5. To raise awareness among the community about the importance of proper waste disposal and recycling.



Methodology:

1. Data Collection: Gather information on solid waste generation, composition, and disposal methods through surveys, interviews, and literature review.

2. Field Surveys: Conduct field surveys to assess the effectiveness of existing waste management practices and infrastructure.

3. Analysis: Analyze the collected data to identify patterns, trends, and areas for improvement.

4. Stakeholder Engagement:Engage with stakeholders including local authorities, community members, and waste management agencies to understand their perspectives and gather insights.

5. Proposed Solutions:Develop recommendations and strategies for improving solid waste management based on the findings.



Observations:

1. High levels of solid waste generation due to population density and urbanization.

2. Inadequate waste collection and disposal infrastructure leading to littering and pollution.

3. Limited public awareness and participation in waste segregation and recycling.

4. Illegal dumping and informal waste picking activities contributing to environmental degradation.



Analysis:

1. The lack of proper waste management infrastructure results in environmental pollution and health hazards.

2. Inefficient waste collection and disposal systems lead to the accumulation of waste in public spaces.

3. Poor waste segregation practices hinder recycling and resource recovery efforts.

4. Limited government funding and institutional capacity impede the implementation of effective waste management strategies.



Results & Conclusion:

1. The study highlights the urgent need for improved solid waste management practices to address environmental concerns and public health risks.

2. Proposed solutions include investment in infrastructure, public awareness campaigns, and regulatory measures to promote waste reduction, recycling, and proper disposal.

3. Collaboration between government agencies, private sector stakeholders, and the community is essential for implementing sustainable waste management initiatives.

4. Continued monitoring and evaluation are necessary to assess the effectiveness of interventions and ensure the long-term sustainability of solid waste management efforts.



In conclusion, effective solid waste management is crucial for mitigating environmental pollution, protecting public health, and promoting sustainable development. By adopting integrated approaches and engaging stakeholders, we can create cleaner and healthier communities for current and future generations.

Wednesday 1 May 2024

ICSE CLASS 10 RESULTS 2024

 


Sunday 28 April 2024

MH RESULTS

 Maharashtra Board Class 10th and 12th Result Dates Announced



Monday 15 April 2024

MH RESULTS 2024

 


Friday 12 April 2024

CLASS 12 PHYSICAL EDUCATION SYLLABUS 2024-25

CLASS 12 PHYSICAL EDUCATION SYLLABUS 2024-25

CLICK BELOW

LINK 1 CLICK HERE 👈👈👈

LINK 2 CLICK HERE 👈👈👈

LINK 3 CLICK HERE 👈👈👈

LINK 4 CLICK HERE 👈👈👈

LINK 5 CLICK HERE 👈👈👈

Monday 1 April 2024

BSC SEM 4 COST

BSC SEM 4 COST

1 .A student received grades of 85, 76, 93, 82, and 96 in five subjects. Determine the arithmetic mean of the grades.

To determine the arithmetic mean (average) of the grades, you add up all the grades and then divide by the number of grades.

Arithmetic Mean =Sum of Grades / Number of Grades

​For the grades of 85, 76, 93, 82, and 96, the sum is:

85+76+93+82+96= 432

There are 5 grades in total. So, the arithmetic mean is:

Arithmetic Mean =432/5

= 86.4


2.The reaction times of an individual to certain stimuli were measured by a psychologist to be 0.53, 0.46, 0.50, 0.49, 0.52, 0.53, 0.44, and 0.55 seconds respectively. Determine the mean reaction time of the individual to the stimuli


To find the mean reaction time of the individual, you need to add up all the measured reaction times and then divide by the number of measurements.

Let's add up the given reaction times:

0.53+0.46+0.50+0.49+0.52+0.53+0.44+0.55=4.920.53+0.46+0.50+0.49+0.52+0.53+0.44+0.55=4.92

Now, there are 8 measurements in total. So, to find the mean reaction time, divide the sum by 8:

Mean Reaction Time=4.928≈0.615Mean Reaction Time=84.92​≈0.615

Therefore, the mean reaction time of the individual to the stimuli is approximately 0.615 seconds.


3. A set of numbers consists of six 6’s, seven 7’s, eight 8’s, nine 9’s and ten 10’s. What is the arithmetic mean of the numbers?

To find the arithmetic mean of a set of numbers, you add up all the numbers and then divide by the total count of numbers.

In this case, you have:


· Six 6's

· Seven 7's

· Eight 8's

· Nine 9's

· Ten 10's


Let's calculate the sum of all these numbers:

(6×6)+(7×7)+(8×8)+(9×9)+(10×10)(6×6)+(7×7)+(8×8)+(9×9)+(10×10) =(36)+(49)+(64)+(81)+(100)=(36)+(49)+(64)+(81)+(100) =330=330

Now, you add up the counts of each number:

6+7+8+9+10=406+7+8+9+10=40

Finally, you divide the sum of all the numbers by the total count of numbers:

Arithmetic Mean=33040=8.25Arithmetic Mean=40330​=8.25

So, the arithmetic mean of the numbers is 8.25.


4. A student’s grades in the laboratory, lecture, and recitation parts of a physics course were 71, 78, and 89, respectively.

(a) If the weights accorded these grades are 2, 4, and 5, respectively, what is an appropriate average grade?

(b) What is the average grade if equal weights are used?

To find the average grade, we will first calculate the weighted average using the given weights, and then we will calculate the average grade with equal weights.

(a) Weighted Average Grade: Given weights for laboratory, lecture, and recitation are 2, 4, and 5 respectively, and the corresponding grades are 71, 78, and 89.

Weighted Average = (Weight for lab * Lab Grade + Weight for lecture * Lecture Grade + Weight for recitation * Recitation Grade) / Total Weight

Weighted Average = (2 * 71 + 4 * 78 + 5 * 89) / (2 + 4 + 5) Weighted Average = (142 + 312 + 445) / 11 Weighted Average = 899 / 11 Weighted Average ≈ 81.73

So, the weighted average grade is approximately 81.73.

(b) Average Grade with Equal Weights: If we use equal weights for all parts (lab, lecture, and recitation), each part will contribute equally to the average.

Average Grade = (Lab Grade + Lecture Grade + Recitation Grade) / 3 Average Grade = (71 + 78 + 89) / 3 Average Grade = 238 / 3 Average Grade ≈ 79.33

So, the average grade with equal weights is approximately 79.33.


5. Three teachers of economics reported mean examination grades of 79, 74, and 82 in their classes, which consisted of 32, 25, and 17 students, respectively. Determine the mean grade for all the classes.

To determine the mean grade for all the classes, we'll first calculate the weighted average of the mean examination grades based on the number of students in each class.

Weighted Average Grade = (Mean Grade for Class 1 * Number of Students in Class 1 + Mean Grade for Class 2 * Number of Students in Class 2 + Mean Grade for Class 3 * Number of Students in Class 3) / Total Number of Students

Given: Mean grade for Class 1 = 79, Number of students in Class 1 = 32 Mean grade for Class 2 = 74, Number of students in Class 2 = 25 Mean grade for Class 3 = 82, Number of students in Class 3 = 17

Weighted Average Grade = (79 * 32 + 74 * 25 + 82 * 17) / (32 + 25 + 17) Weighted Average Grade = (2528 + 1850 + 1394) / 74 Weighted Average Grade = 5772 / 74 Weighted Average Grade ≈ 78.00

So, the mean grade for all the classes is approximately 78.00.


6. Find the mean and median of these sets of numbers:

(a) 5, 4, 8, 3, 7, 2, 9

(b) 18.3, 20.6, 19.3, 22.4, 20.2, 18.8, 19.7, 20.0

Let's find the mean and median for each set of numbers:

(a) Set of numbers: 5, 4, 8, 3, 7, 2, 9

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (5 + 4 + 8 + 3 + 7 + 2 + 9) / 7 Mean = 38 / 7 Mean ≈ 5.43

To find the median: First, arrange the numbers in ascending order: 2, 3, 4, 5, 7, 8, 9 Since there are 7 numbers, the median will be the middle number, which is 5.

So, for set (a), the mean is approximately 5.43 and the median is 5.

(b) Set of numbers: 18.3, 20.6, 19.3, 22.4, 20.2, 18.8, 19.7, 20.0

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (18.3 + 20.6 + 19.3 + 22.4 + 20.2 + 18.8 + 19.7 + 20.0) / 8 Mean = 159.3 / 8 Mean = 19.91

To find the median: First, arrange the numbers in ascending order: 18.3, 18.8, 19.3, 19.7, 20.0, 20.2, 20.6, 22.4 Since there are 8 numbers, the median will be the average of the middle two numbers, which are 19.7 and 20.0. Median = (19.7 + 20.0) / 2 Median = 39.7 / 2 Median = 19.85

So, for set (b), the mean is 19.91 and the median is 19.85.


7. Find the mean, median, and mode for each set of numbers:

(a) 7, 4, 10, 9, 15, 12, 7, 9, 7

(b) 8, 11, 4, 3, 2, 5, 10, 6, 4, 1, 10, 8, 12, 6, 5, 7

1. t's find the mean, median, and mode for each set of numbers:

(a) Set of numbers: 7, 4, 10, 9, 15, 12, 7, 9, 7

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (7 + 4 + 10 + 9 + 15 + 12 + 7 + 9 + 7) / 9 Mean = 80 / 9 Mean ≈ 8.89

To find the median: First, arrange the numbers in ascending order: 4, 7, 7, 7, 9, 9, 10, 12, 15 Since there are 9 numbers, the median will be the middle number, which is 9.

To find the mode: The mode is the number that appears most frequently in the set. In this case, 7 appears three times, making it the mode.

So, for set (a), the mean is approximately 8.89, the median is 9, and the mode is 7.

(b) Set of numbers: 8, 11, 4, 3, 2, 5, 10, 6, 4, 1, 10, 8, 12, 6, 5, 7

Mean (Average): Mean = (Sum of all numbers) / (Number of numbers) Mean = (8 + 11 + 4 + 3 + 2 + 5 + 10 + 6 + 4 + 1 + 10 + 8 + 12 + 6 + 5 + 7) / 16 Mean = 102 / 16 Mean = 6.375

To find the median: First, arrange the numbers in ascending order: 1, 2, 3, 4, 4, 5, 5, 6, 6, 7, 8, 8, 10, 10, 11, 12 Since there are 16 numbers, the median will be the average of the middle two numbers, which are 6 and 6. Median = (6 + 6) / 2 Median = 12 / 2 Median = 6

To find the mode: The mode is the number that appears most frequently in the set. In this case, both 4 and 10 appear twice, making them the modes.

So, for set (b), the mean is 6.375, the median is 6, and the modes are 4 and 10.

8.Find the geometric mean of the numbers a) 4.2 and 16.8

To find the geometric mean of two numbers, you multiply them together and then take the square root of the product. The formula for the geometric mean of two numbers �a and �b is:

Geometric Mean=�×�Geometric Mean=a×b​

For the numbers 4.2 and 16.8, we can plug them into the formula:

Geometric Mean=4.2×16.8Geometric Mean=4.2×16.8​

Geometric Mean=70.56Geometric Mean=70.56​

Geometric Mean≈8.4Geometric Mean≈8.4

So, the geometric mean of 4.2 and 16.8 is approximately 8.4.a


Find the range of the sets (a) 5, 3, 8, 4, 7, 6, 12, 4, 3 and (b) 8.772, 6.453, 10.624, 8.628, 9.434, 6.351

To find the range of a set of numbers, you need to subtract the smallest number from the largest number in the set. Let's calculate the range for each set:

(a) Set: 5, 3, 8, 4, 7, 6, 12, 4, 3 The smallest number in the set is 3, and the largest number is 12. Range = Largest number - Smallest number Range = 12 - 3 = 9 So, the range of set (a) is 9.

(b) Set: 8.772, 6.453, 10.624, 8.628, 9.434, 6.351 The smallest number in the set is 6.351, and the largest number is 10.624. Range = Largest number - Smallest number Range = 10.624 - 6.351 ≈ 4.273 (rounded to three decimal places) So, the range of set (b) is approximately 4.273.



Find the mean deviation of the set (a)3,7,9,5and(b) 2.4, 1.6, 3.8, 4.1, 3.4

To find the mean deviation of a set of numbers, follow these steps:Calculate the mean (average) of the set.
Find the absolute difference between each number in the set and the mean.
Calculate the mean of these absolute differences.

Let's start with set (a):

a) Set: 3, 7, 9, 5Mean (average) = (3 + 7 + 9 + 5) / 4 = 24 / 4 = 6

Now, find the absolute differences between each number and the mean:

|3 - 6| = 3 |7 - 6| = 1 |9 - 6| = 3 |5 - 6| = 1Calculate the mean of these absolute differences:

Mean deviation = (3 + 1 + 3 + 1) / 4 = 8 / 4 = 2

So, the mean deviation of set (a) is 2.

Now, let's move on to set (b):

b) Set: 2.4, 1.6, 3.8, 4.1, 3.4Mean (average) = (2.4 + 1.6 + 3.8 + 4.1 + 3.4) / 5 = 15.3 / 5 = 3.06

Now, find the absolute differences between each number and the mean:

|2.4 - 3.06| = 0.66 |1.6 - 3.06| = 1.46 |3.8 - 3.06| = 0.74 |4.1 - 3.06| = 1.04 |3.4 - 3.06| = 0.34Calculate the mean of these absolute differences:

Mean deviation = (0.66 + 1.46 + 0.74 + 1.04 + 0.34) / 5 ≈ 0.864

So, the mean deviation of set (b) is approximately 0.864.




Basic syntax

Basic syntax refers to the fundamental rules and structure that govern how programming languages are written. Each programming language has its own syntax, which includes rules for writing code, organizing statements, defining variables, and specifying actions or functions. Here are some key components of basic syntax:

Statements: A statement is a single line of code that performs a specific task. Statements can include variable declarations, function calls, conditional expressions, loops, and more.


Variables: Variables are used to store data values that can be manipulated and accessed throughout the program. They are typically declared with a specific data type (e.g., integer, string, boolean) and a name that uniquely identifies them within the program.


Data Types: Programming languages support various data types, such as integers, floating-point numbers, strings, characters, booleans, arrays, and objects. Each data type has specific rules for how data is stored and manipulated.


Operators: Operators are symbols or keywords that perform operations on one or more operands. Examples of operators include arithmetic operators (+, -, *, /), comparison operators (==, !=, <, >), logical operators (&&, ||, !), and assignment operators (=, +=, -=).


Control Structures: Control structures are used to control the flow of execution in a program. Common control structures include conditional statements (if-else, switch), loops (for, while, do-while), and branching statements (break, continue, return).





Monday 25 March 2024

MHCET revised exam dates

Maharastra MHCET revised exam dates 

See below 👇👇👇








Saturday 23 March 2024

Class 11 QB solutions

 Class 11 QB solutions

chapter 1 click here 👈👈👈

chapter 5 click here 👈👈👈

chapter 6 click here 👈👈👈

chapter 7 click here 👈👈👈

chapter 8 click here 👈👈👈

chapter 10 click here 👈👈👈

chapter 11 click here 👈👈👈

chapter 14 click here 👈👈👈


Saturday 16 March 2024

MHCET-2024 IMP Questions

 MHCET-24 IMP Questions 



chapter wise  weighted click here👈👈👈👈

sample papers click here 👈👈👈👈

Thursday 14 March 2024

QB SOLUTIONS CLASS 11 CHEMISTRY

 QB SOLUTIONS CLASS 11 CHEMISTRY 

Periodic table 

any two characteristics of s block elements

They are soft metals, possess low melting and boiling points, have the largest atomic radii in their corresponding periods and are good conductors of heat and electricity. 

They have low values of ionization energies and are hence highly electropositive.


define ionization energy and electronegativity

Ionization Energy and Electronegativity are the inverse of each other. Electronegativity is an atom's tendency to attract an electron. In contrast, the ionization energy is the energy needed to remove an electron from an atom.

1s2 2s2 2p1 is the electronic configuration of Boron

1s2 2s1 is the electronic configuration of lithium 

states of matter 

boyles law : Boyle's law is a gas law which states that the pressure exerted by a gas (of a given mass, kept at a constant temperature) is inversely proportional to the volume occupied by it.

charles law click here 👈👈

derive ideal gas equation 👈👈👈 click here 

a sample of gas heated click here 👈👈👈


some basic concepts of chemistry 

avagadros law click here 👈👈

law of conservation of mass click here 👈👈

gay lussac law click here 👈👈👈


Saturday 10 February 2024

H.S.C 2024 V.S.A

 H.S.C 2024 V.S.A ( 1 MARK QUESTIONS)

C.H.P 1

find the radius of gyration of a uniform disc about an axis perpendicular to the plane

does angle of banking depend upon the mass of vehicle 

during ice ballet while in outer rounds why do dancers outstretch their arms 

state principle of conservation of angular momentum

what is well of death

C.H.P 2

surface film 

cohesive forces

shape of meniscus for obtuse angle of contact

net weight of body when it passes through terminal velocity

common unit for measuring pressure of a gas

equation of continuity

C.H.P 3

under what conditions are boyles, gay lussac and charles law valid

on what values co efficients a,e,t depend 

why temperature of all bodies are constant at room temperature

above what temperature do bodies emit electromagnetic radiation 

state formula for mean free path 

C.H.P 4

when 2 objects are said to be in thermal equilibrium 

science of measuring temperature is called

zeroth law of thermodynamics

energy of random disordered motion of molecules is called as 

group of objects that have ability to exchange energy with surroundings is called

on what basis thermodynamic system can be classified

define heat 

what is internal energy of system when heat Q is added to system that does not do any work

when does a system loose heat to surroundings

first law of thermodynamics

what are heat engines 

equation of effiency of carnot engines.

C.H.P 5

simple pendulum moves from one end to other in 1/4 second what is its frequency

a simple pendulum is inside a spacecraft what will be its time period 

what is amplitude of SHM 

what is seconds pendulum

formula of frequency of SHM in terms of force constant k

what is phase of 90 indicate in SHM 

C.H.P 6

what is interference of sound waves

what are beats

harmonics

overtones

law of length

law of tension

law of linear density

what is resonance

what are forced vibrations 

one characteristics of sound

C.H.P 7 



Saturday 13 January 2024

Marathi Grammar



Marathi Grammar

ā¤…ā¤°्ā¤Ĩाā¤ĩā¤°ूā¤¨ ā¤ĩाā¤•्ā¤¯ाā¤šे ā¤Ē्ā¤°ā¤•ाā¤° :
ā¤ĩिā¤§ाā¤¨ाā¤¤्ā¤Žā¤• ā¤ĩाā¤•्ā¤¯ : ā¤Žी ā¤Žā¤°ाā¤ ी ā¤ĩाā¤šā¤¤ो.
ā¤Ē्ā¤°ā¤ļ्ā¤¨ाā¤°्ā¤Ĩā¤• ā¤ĩाā¤•्ā¤¯ : ā¤¤ु ā¤Žā¤°ाā¤ ी ā¤ĩाā¤šā¤¤ो ?
ā¤†ā¤œ्ā¤žाā¤°्ā¤Ĩी ā¤ĩाā¤•्ā¤¯ : ā¤šिंā¤Ļी ā¤ĩाā¤šा.
ā¤‰ā¤Ļā¤—ाā¤° ā¤ĩाā¤šā¤• ā¤ĩाā¤•्ā¤¯ : ā¤ĩाā¤š ! ā¤–ूā¤Ē ā¤Žोā¤ े ā¤†ā¤šे.
ā¤¨ā¤•ाā¤°ाā¤¤्ā¤Žā¤• ā¤ĩाā¤•्ā¤¯ : ā¤Žी ā¤—ā¤Ŗिā¤¤ ā¤ĩाā¤šā¤¤ ā¤¨ाā¤šी .
ā¤šोā¤•ाā¤°ाā¤¤्ā¤Žā¤• ā¤ĩाā¤•्ā¤¯ : ā¤Žी ā¤—ā¤Ŗिā¤¤ ā¤¸ोā¤Ąā¤ĩā¤¤ो



Meaning in English
Types of Sentences by Meaning:
Declarative sentence : I read Marathi.
Interrogative sentence: Do you read Marathi?
Imperative Sentence : Read Hindi.
Excited Reader Sentence: Wow! is very large.
Negative sentence: I don't read mathematics.
Affirmative Sentence : I solve mathematics.

Saturday 6 January 2024

H.S.C 2024 ( MOST EXPECTED QUESTIONS ) PHYSICS

 H.S.C 2024 ( MOST EXPECTED QUESTIONS )

PHYSICS 

CHAPTER 1 (ROTATIONAL DYNAMICS)

STATE AND PROVE THE THEOREM OF PARALLEL AXIS (4M)

DERIVE AN EXPRESSION FOR TIME PERIOD OF CONICAL PENDULUM (3M)

FOR A CONICAL PENDULUM PROVE THAT TAN  = V2/RG (3M)

IF THE FRICTION IS MADE ZERO CAN THE VEHICLE MOVE SAFELY ON THE ROAD (1M)

STATE AND PROVE THE PRINCIPLE OF CONSERVATION OF ANGULAR MOMENTUM (2M)

DERIVE EXPRESSIONS FOR LINEAR VELOCITY AT LOWEST POINT, MIDWAY AND TOP POSITION, FOR A PARTICLE REVOLVING IN A VERTICAL CIRCLE IF IT HAS TO COMPLETE JUST CIRCULAR MOTION (VCM) (4M)

                                 OR

USING ENERGY CONSERVATION DERIVE EXPRESSIONS FOR LINEAR VELOCITY AT LOWEST POINT, MIDWAY AND TOP POSITION, FOR A PARTICLE REVOLVING IN A VERTICAL CIRCLE IF IT HAS TO COMPLETE JUST CIRCULAR MOTION (VCM) (4M)

DEFINE MOMENT OF INERTIA OF A RIGID BODY. STATE ITS SI UNIT AND DIMENSIONS (2M)

DERIVE AN EXPRESSION FOR KINETIC ENERGY OF A ROTATING BODY WITH UNIFORM ANGULAR SPEED (2M)

SHOW THAT K.E OF A ROTATING BODY IS EQUAL TO 1/2L.W, L IS ANGULAR MOMENTUM (2M)

STATE THE FORMULA FOR MOMENT OF INERTIA OF A SOLID SPHERE ABOUT AN AXIS PASSING THROUGH ITS CENTRE (1M)

DEFINE UNIFORM CIRCULAR MOTION (2M)

OBTAIN THE RELATION BETWEEN MAGNITUDE OF LINEAR AND ANGULAR ACCELERATION IN UCM (2M)

WHAT IS THE VALUE OF TANGENTIAL ACCELERATION IN UCM (1M)

WHAT IS RADIUS OF GYRATION? WRITE ITS PHYSICAL SIGNIFICANCE (2M)

EXPLAIN THE CONCEPT OF CENTRIPITAL FORCE (2M)

NAME THE FORCES ACTING ON A BODY PERFORMING NON UCM (2M)

OBTAIN AN EXPRESSION FOR MAXIMUAM SAFE SPEED FOR A VEHICLE ON A BANKED ROAD (3M)

OBTAIN AN EXPRESSION FOR MI OF SOLID UNIFORM DISC AXIS PASSING THROUGH CENTER AND PERPENDICULAR TO THE PLANE (3M)

OBTAIN AN EXPRESSION FOR KINETIC ENERGY OF A BODY PERFORMING ROLLING MOTION OR A ROLLING BODY

(4M)

OBTAIN AN EXPRESSION FOR TORQUE IN TERMS OF MOMENT OF INERTIA

PERPENDICULAR AXIS THEOREM

SPHERE OF DEATH

CPF AND CFF DIFFERENCE